# Time & Distance

﻿

### Important Formulas

1. Speed=Distance/Time
2. Distance=Speed × Time
3. Time=Distance/Speed
4. To convert Kilometers per Hour(km/hr) to Meters per Second(m/s)
x km/hr=(x×5)/18m/s
5. To convert Meters per Second(m/s) to Kilometers per Hour(km/hr)
x m/s=(x×18)/5 km/hr
6. If a car covers a certain distance at x kmph and an equal distance at y kmph, the average speed of the whole journey = 2xy/(x+y) kmph
7. Speed and time are inversely proportional (when distance is constant) Speed  1/Time (when distance is constant)
8. If the ratio of the speeds of A and B is a : b, then the ratio of the times taken by them to cover the same distance is 1/a:1/b or b : a

Solved Examples

Level 1

 1. A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour? A. 8.2 B. 4.2 C. 6.1 D. 7.2

AnswerOption D

Explanation :

Distance = 600 meter

time = 5 minutes = 5 x 60 seconds = 300 seconds

Speed = distance/time=600/300=2m/s=(2×18)/5 km/hr=36/5 km/hr=7.2 km/hr

 2. Two boys starts from the same place walking at the rate of 5 kmph and 5.5 kmph respectively in the same direction. What time will they take to be 8.5 km apart? A. 17 hr B. 14 hr C. 12 hr D. 19 hr

AnswerOption A

Explanation :

Relative speed = 5.5 – 5 = .5 kmph (because they walk in the same direction)

distance = 8.5 km

Time = distance/speed=8.5/.5=17 hr.

 3. Walking 6/7th of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover that distance? A. 1 hr 42 min B. 1 hr C. 2 hr D. 1 hr 12 min

AnswerOption D

Explanation :

New speed = 6/7 of usual speed
Speed and time are inversely proportional.
Hence new time = 7/6 of usual time
Hence, 7/6 of usual time – usual time = 12 minutes
=> 1/6 of usual time = 12 minutes => usual time = 12 x 6 = 72 minutes = 1 hour 12 minutes

 4. A man goes to his office from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming, what is the distance between his house and office? A. 3 km B. 4 km C. 5 km D. 6 km

AnswerOption D

Explanation :

If a car covers a certain distance at x kmph and an equal distance at y kmph,the average speed of the whole journey = 2xy/(x+y) kmph

Hence, average speed = (2×3×2)/(2+3)=12/5 km/hr .

Total time taken = 5 hours

Distance travelled = (12/5)×5=12 km

Distance between his house and office =12/2=6 km

 5. If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. What is the actual distance travelled by him? A. 80 km B. 70 km C. 60 km D. 50 km

AnswerOption D

Explanation :

Assume that the person would have covered x km if travelled at 10 km/hr

Speed = Distance/Time=x/10….. (Equation1)

Give that the person would have covered (x + 20) km if travelled at 14 km/hr

Speed = Distance/Time=(x+20)/14….. (Equation2)

From Equations 1 and 2,

X/10=(x+20)/14 14x=10x+200 4x=200 x=200/4=50

 6. A car travels at an average of 50 miles per hour for 212 hours and then travels at a speed of 70 miles per hour for 112 hours. How far did the car travel in the entire 4 hours? A. 210 miles B. 230 miles C. 250 miles D. 260 miles

AnswerOption B

Explanation :

Speed1 = 50 miles/hour

Time1 = 2*(1/2) hour=5/2 hour

Distance1 = Speed1 × Time1 = (50×5)/2=25×5=125 miles

Speed2 = 70 miles/hour

Time2 = 1*1/2 hour=3/2 hour

Distance2 = Speed2 × Time2 = 70×3/2=35×3=105 miles

Total Distance = Distance1 + Distance2 =125+105=230 miles

 7. Sound is said to travel in air at about 1100 feet per second. A man hears the axe striking the tree, 11/5 seconds after he sees it strike the tree. How far is the man from the wood chopper? A. 1800 ft B. 2810 ft C. 3020 ft D. 2420 ft

AnswerOption D

Explanation :

Speed of the sound = 1100 ft/s Time = 11/5 second

Distance = Speed × Time = 1100 ×11/5=220×11=2420 ft

 8. A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. What is the length of the bridge (in meters)? A. 1250 B. 1280 C. 1320 D. 1340

AnswerOption A

Explanation :

Speed = 5 km/hr

Time = 15 minutes = 1/4 hour

Length of the bridge = Distance Travelled by the man

= Speed × Time = 5×1/4 km

=5×1/4×1000 metre=1250 metre

Level 2

 1. A man takes 5 hours 45 min in walking to a certain place and riding back. He would have gained 2 hours by riding both ways. The time he would take to walk both ways is A. 11 hrs B. 8 hrs 45 min C. 7 hrs 45 min D. 9 hts 20 min

AnswerOption C

Explanation :

 Given that time taken for riding both ways will be 2 hours lesser than the time needed for waking one way and riding backFrom this, we can understand that time needed for riding one way = time needed for waking one way – 2 hoursGiven that time taken in walking one way and riding back = 5 hours 45 minHence The time he would take to walk both ways = 5 hours 45 min + 2 hours = 7 hours 45 minIn fact, you can do all these calculations mentally and save a lot of time which will be a real benefit for you.  2. A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km. A. 121 km B. 242 km C. 224 km D. 112 km

AnswerOption C

Explanation :

distance = speed x time
Let time taken to travel the first half = x hr
then time taken to travel the second half = (10 – x) hr
Distance covered in  the first half = 21x
Distance covered in  the second half = 24(10 – x)
But distance covered in  the first half = Distance covered in the second half
=> 21x = 24(10 – x) => 21x = 240 – 24x => 45x = 240 => 9x = 48 => 3x = 16
x=16/3

Hence Distance covered in the first half = 21x=21×16/3=7×16=112 km. Total distance = 2×112=224 km

 3. A car traveling with 5/7 of its actual speed covers 42 km in 1 hr 40 min 48 sec. What is the actual speed of the car? A. 30 km/hr B. 35 km/hr C. 25 km/hr D. 40 km/hr

AnswerOption B

Explanation :

Time = 1 hr 40 min 48 sec = 1hr +40/60hr+48/3600hr=1+2/3+1/75=126/75hr

Distance = 42 km Speed=distance/time=42(126/75) =42×75/126

5/7 of the actual speed = 42×75/126

actual speed = 42×75/126×7/5=42×15/18=7×15/3=7×5=35 km/hr

 4. A man covered a certain distance at some speed. If he had moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. What is the the distance in km? A. 36 B. 38 C. 40 D. 42

AnswerOption C

Explanation :

Let the distance be x km , the speed in which he moved = v kmph

Time taken when moving at normal speed – time taken when moving 3 kmph faster = 40 minutes

x/v−x/(v+3)=40/60 x[1/v−1/(v+3)]=2/3 x[(v+3−v)/v(v+3)]=2/3

2v(v+3)=9x…………….(Equation1)

Time taken when moving 2 kmph slower – Time taken when moving at normal speed = 40 minutes

x/(v−2)−x/v=40/60 x[1/(v−2)−1/v]=2/3

x[(v−v+2)/v(v−2)]=2/3 x[2/v(v−2)]=2/3

x[1/v(v−2)]=1/3 v(v−2)=3x…………….(Equation2)

Equation1/Equation2

2(v+3)/(v−2)=3 2v+6=3v−6v=12

Substituting this value of v inEquation12×12×15=9x

=>x= (2×12×15)/9= (2×4×15)/3=2×4×5=40. Hence distance = 40 km

 5. In covering a distance of 30 km, Arun takes 2 hours more than Anil. If Arun doubles his speed, then he would take 1 hour less than Anil. What is Arun’s speed? A. 8 kmph B. 5 kmph C. 4 kmph D. 7 kmph

AnswerOption B

Explanation :

Let the speed of Arun = x kmph and the speed of Anil = y kmph
distance = 30 km

We know that  distance/speed = time. Hence, 30/x−30/y=2………..(Equation1)

30/y−30/2x=1………..(Equation2)

Equation1 + Equation230/x−30/2x=3 30/2x=3 15/x=3 5/x=1x=5. Hence Arun’s speed = 5 kmph

 6. A car travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour? A. 70.24 km/hr B. 74. 24 km/hr C. 71.11 km/hr D. 72.21 km/hr

AnswerOption C

Explanation :

If a car covers a certain distance at x kmph and an equal distance at y kmph,the average speed of the whole journey = 2xy/(x+y) kmph.

By using the same formula, we can find out the average speed quickly average speed = (2×64×80)/(64+80)=(2×64×80)/144 (2×32×40)/36 = (2×32×10)/9 (64×10)/9=71.11 kmph

 7. A man rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. What is his average speed for the entire trip approximately? A. 11.2 kmph B. 10 kmph C. 10.2 kmph D. 10.8 kmph

AnswerOption D

Explanation :

Total distance travelled = 10 + 12 = 22 km

Time taken to travel 10 km at an average speed of 12 km/hr = distance/speed=10/12 hr

Time taken to travel 12 km at an average speed of 10 km/hr = distance/speed=12/10 hr

Total time taken =10/12+12/10 hr

Average speed = distance/time=22/(10/12+12/10)=(22×120)/{(10×10)+(12×12)}

(22×120)/244=(11×120)/122=(11×60)/61=660/61≈10.8 kmph

 8. An airplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 123 hours, it must travel at a speed of: A. 660 km/hr B. 680 km/hr C. 700 km/hr D. 720 km/hr

AnswerOption D

Explanation :

Speed and time are inversely proportional Speed  1/Time (when distance is constant)

Here distance is constant and Speed and time are inversely proportional

Speed  1/TimeSpeed1/Speed2=Time2/Time1

240/Speed2=(1*2/3)5240/Speed2=(5/3)/5240/Speed2=1/3 Speed2=240×3=720 km/hr

 9. A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. What is the speed of the car? A. 80 kmph B. 102 kmph C. 120 kmph D. 140 kmph

AnswerOption C

Explanation :

Let speed of the car = x kmph

Then speed of the train = x *(100+50)/100=150 x /100=3 x /2 kmph

Time taken by the car to travel from A to B=75/x hours

Time taken by the train to travel from A to B=75/(3 x /2)+12.5/60 hours

Since both start from A at the same time and reach point B at the same time

75/x=75/(3 x /2)+12.5/60 25/x=12.5/60 x=(25×60)/12.5=2×60=120

GPSC Notes brings Prelims and Mains programs for GPSC Prelims and GPSC Mains Exam preparation. Various Programs initiated by GPSC Notes are as follows:- For any doubt, Just leave us a Chat or Fill us a querry––
error: Content is protected !!
English
English
ગુજરાતી